Integrand size = 20, antiderivative size = 30 \[ \int \csc ^3(2 a+2 b x) \sin ^2(a+b x) \, dx=\frac {\log (\tan (a+b x))}{8 b}+\frac {\tan ^2(a+b x)}{16 b} \]
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Time = 0.06 (sec) , antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {4373, 2700, 14} \[ \int \csc ^3(2 a+2 b x) \sin ^2(a+b x) \, dx=\frac {\tan ^2(a+b x)}{16 b}+\frac {\log (\tan (a+b x))}{8 b} \]
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Rule 14
Rule 2700
Rule 4373
Rubi steps \begin{align*} \text {integral}& = \frac {1}{8} \int \csc (a+b x) \sec ^3(a+b x) \, dx \\ & = \frac {\text {Subst}\left (\int \frac {1+x^2}{x} \, dx,x,\tan (a+b x)\right )}{8 b} \\ & = \frac {\text {Subst}\left (\int \left (\frac {1}{x}+x\right ) \, dx,x,\tan (a+b x)\right )}{8 b} \\ & = \frac {\log (\tan (a+b x))}{8 b}+\frac {\tan ^2(a+b x)}{16 b} \\ \end{align*}
Time = 0.03 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.43 \[ \int \csc ^3(2 a+2 b x) \sin ^2(a+b x) \, dx=\frac {1}{8} \left (-\frac {\log (\cos (a+b x))}{b}+\frac {\log (\sin (a+b x))}{b}+\frac {\sec ^2(a+b x)}{2 b}\right ) \]
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Time = 0.99 (sec) , antiderivative size = 24, normalized size of antiderivative = 0.80
method | result | size |
default | \(\frac {\frac {1}{2 \cos \left (x b +a \right )^{2}}+\ln \left (\tan \left (x b +a \right )\right )}{8 b}\) | \(24\) |
risch | \(\frac {{\mathrm e}^{2 i \left (x b +a \right )}}{4 b \left ({\mathrm e}^{2 i \left (x b +a \right )}+1\right )^{2}}-\frac {\ln \left ({\mathrm e}^{2 i \left (x b +a \right )}+1\right )}{8 b}+\frac {\ln \left ({\mathrm e}^{2 i \left (x b +a \right )}-1\right )}{8 b}\) | \(63\) |
parallelrisch | \(\frac {-\csc \left (x b +a \right )^{2} \left (\sec \left (x b +a \right )^{2}-2\right ) \cos \left (2 x b +2 a \right )-2 \csc \left (x b +a \right ) \sec \left (x b +a \right ) \sin \left (2 x b +2 a \right )+16 \ln \left (\tan \left (x b +a \right )^{\frac {1}{4}}\right )+\csc \left (x b +a \right )^{2} \left (\sec \left (x b +a \right )^{2}-2\right )}{32 b}\) | \(89\) |
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Leaf count of result is larger than twice the leaf count of optimal. 56 vs. \(2 (26) = 52\).
Time = 0.25 (sec) , antiderivative size = 56, normalized size of antiderivative = 1.87 \[ \int \csc ^3(2 a+2 b x) \sin ^2(a+b x) \, dx=-\frac {\cos \left (b x + a\right )^{2} \log \left (\cos \left (b x + a\right )^{2}\right ) - \cos \left (b x + a\right )^{2} \log \left (-\frac {1}{4} \, \cos \left (b x + a\right )^{2} + \frac {1}{4}\right ) - 1}{16 \, b \cos \left (b x + a\right )^{2}} \]
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Timed out. \[ \int \csc ^3(2 a+2 b x) \sin ^2(a+b x) \, dx=\text {Timed out} \]
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Leaf count of result is larger than twice the leaf count of optimal. 641 vs. \(2 (26) = 52\).
Time = 0.21 (sec) , antiderivative size = 641, normalized size of antiderivative = 21.37 \[ \int \csc ^3(2 a+2 b x) \sin ^2(a+b x) \, dx=\frac {4 \, \cos \left (4 \, b x + 4 \, a\right ) \cos \left (2 \, b x + 2 \, a\right ) + 8 \, \cos \left (2 \, b x + 2 \, a\right )^{2} - {\left (2 \, {\left (2 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right )} \cos \left (4 \, b x + 4 \, a\right ) + \cos \left (4 \, b x + 4 \, a\right )^{2} + 4 \, \cos \left (2 \, b x + 2 \, a\right )^{2} + \sin \left (4 \, b x + 4 \, a\right )^{2} + 4 \, \sin \left (4 \, b x + 4 \, a\right ) \sin \left (2 \, b x + 2 \, a\right ) + 4 \, \sin \left (2 \, b x + 2 \, a\right )^{2} + 4 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right )} \log \left (\cos \left (2 \, b x\right )^{2} + 2 \, \cos \left (2 \, b x\right ) \cos \left (2 \, a\right ) + \cos \left (2 \, a\right )^{2} + \sin \left (2 \, b x\right )^{2} - 2 \, \sin \left (2 \, b x\right ) \sin \left (2 \, a\right ) + \sin \left (2 \, a\right )^{2}\right ) + {\left (2 \, {\left (2 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right )} \cos \left (4 \, b x + 4 \, a\right ) + \cos \left (4 \, b x + 4 \, a\right )^{2} + 4 \, \cos \left (2 \, b x + 2 \, a\right )^{2} + \sin \left (4 \, b x + 4 \, a\right )^{2} + 4 \, \sin \left (4 \, b x + 4 \, a\right ) \sin \left (2 \, b x + 2 \, a\right ) + 4 \, \sin \left (2 \, b x + 2 \, a\right )^{2} + 4 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right )} \log \left (\cos \left (b x\right )^{2} + 2 \, \cos \left (b x\right ) \cos \left (a\right ) + \cos \left (a\right )^{2} + \sin \left (b x\right )^{2} - 2 \, \sin \left (b x\right ) \sin \left (a\right ) + \sin \left (a\right )^{2}\right ) + {\left (2 \, {\left (2 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right )} \cos \left (4 \, b x + 4 \, a\right ) + \cos \left (4 \, b x + 4 \, a\right )^{2} + 4 \, \cos \left (2 \, b x + 2 \, a\right )^{2} + \sin \left (4 \, b x + 4 \, a\right )^{2} + 4 \, \sin \left (4 \, b x + 4 \, a\right ) \sin \left (2 \, b x + 2 \, a\right ) + 4 \, \sin \left (2 \, b x + 2 \, a\right )^{2} + 4 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right )} \log \left (\cos \left (b x\right )^{2} - 2 \, \cos \left (b x\right ) \cos \left (a\right ) + \cos \left (a\right )^{2} + \sin \left (b x\right )^{2} + 2 \, \sin \left (b x\right ) \sin \left (a\right ) + \sin \left (a\right )^{2}\right ) + 4 \, \sin \left (4 \, b x + 4 \, a\right ) \sin \left (2 \, b x + 2 \, a\right ) + 8 \, \sin \left (2 \, b x + 2 \, a\right )^{2} + 4 \, \cos \left (2 \, b x + 2 \, a\right )}{16 \, {\left (b \cos \left (4 \, b x + 4 \, a\right )^{2} + 4 \, b \cos \left (2 \, b x + 2 \, a\right )^{2} + b \sin \left (4 \, b x + 4 \, a\right )^{2} + 4 \, b \sin \left (4 \, b x + 4 \, a\right ) \sin \left (2 \, b x + 2 \, a\right ) + 4 \, b \sin \left (2 \, b x + 2 \, a\right )^{2} + 2 \, {\left (2 \, b \cos \left (2 \, b x + 2 \, a\right ) + b\right )} \cos \left (4 \, b x + 4 \, a\right ) + 4 \, b \cos \left (2 \, b x + 2 \, a\right ) + b\right )}} \]
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Time = 0.34 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.37 \[ \int \csc ^3(2 a+2 b x) \sin ^2(a+b x) \, dx=-\frac {\frac {1}{\sin \left (b x + a\right )^{2} - 1} + \log \left (-\sin \left (b x + a\right )^{2} + 1\right ) - 2 \, \log \left ({\left | \sin \left (b x + a\right ) \right |}\right )}{16 \, b} \]
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Time = 0.11 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.17 \[ \int \csc ^3(2 a+2 b x) \sin ^2(a+b x) \, dx=\frac {\frac {\ln \left ({\sin \left (a+b\,x\right )}^2\right )}{16}-\frac {\ln \left (\cos \left (a+b\,x\right )\right )}{8}+\frac {1}{16\,{\cos \left (a+b\,x\right )}^2}}{b} \]
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